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X^2+6X=1216
We move all terms to the left:
X^2+6X-(1216)=0
a = 1; b = 6; c = -1216;
Δ = b2-4ac
Δ = 62-4·1·(-1216)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-70}{2*1}=\frac{-76}{2} =-38 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+70}{2*1}=\frac{64}{2} =32 $
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